Electrician (ELE)

Third Period Package (25 Modules) Comments

Date: 9/26/2022 8:03:21 AM
Module: 030301d
Version: 24
Page: 58
Comment: Self-Test Answers, answer for question 4: please change b) to a) in the answer. 6.4 A is the correct value. The multiple-choice question is on page 52. It appears that the answers were accidentally mixed up.
Status: Implemented

Date: 9/29/2022 2:37:06 PM
Module: 030301e
Version: 24
Page: 7
Comment: Below Figure 5: In Figure 5, the phasors have been rotated 30°. This places the line current phasors as follows: "This places the line 'current' phasors as follows" should read "This places the line 'voltage' phasors as follows". The information is intended to describe the placement of 'voltage' phasors.
Status: Implemented

Date: 1/31/2020 3:59:14 PM
Module: 030302b
Version: 21
Page: 25
Comment: 030302b – Page 25 – Table 5 – Breakdown torque values are backwards. In order to be consistent with Module A and the info in module B, it should be: Design A - Normal Breakdown Torque Design B - Normal Breakdown Torque Design C - High Breakdown Torque Design D - Very High Breakdown Torque
Status: Update in Progress

Date: 9/12/2022 10:22:22 AM
Module: 030302b
Version: 24
Page: 12
Comment: Change the sentence describing Figure 2 from - "Torque breakdown point at high point of the Ir(x) curve when ..." to "Torque breakdown point is at the high point of the Ir(R) curve when ..."
Status: Implemented

Date: 9/12/2022 10:26:16 AM
Module: 030302b
Version: 24
Page: 37
Comment: Objective 5 exercise answer 1 should say: b) False; speed control of a wound rotor motor is most suitable from HALF to full load speed (not 0 rpm to full-load speed).
Status: Implemented

Date: 9/12/2022 10:16:04 AM
Module: 030302b
Version: 24
Page: 9
Comment: 1. the slip speed formula transposed for slip is Ns/Nsyn not Nr. 2. There is no transposition for slip for the speed of the rotor formula (Nr = Nsyn-Ns) because it doesn't include slip (only slip speed). The formula written in the box is correct just not a transposition.
Status: Implemented

Date: 11/21/2022 2:12:37 PM
Module: 030304a
Version: 24
Page: 15
Comment: The service raceway bonding jumpers in Figures 7 and 14 must be terminated on a separate bonding lug as per Figures 2, 3, and 9 in the same module.
Status: Implemented

Date: 11/10/2022 8:31:47 AM
Module: 030304b
Version: 24
Page:
Comment: Figure 24: No. 1 (130A)* Figure 25: 600 kcmil RW90 (420A)*
Status: Implemented

Date: 11/10/2022 8:45:58 AM
Module: 030304b
Version: 24
Page: 39
Comment: Figure 28 is misleading as there is no explanation for conductor 'C' being sized based on the Line Voltage ratio. It simply says ratio. Transformer ratios are based on phase voltage values not line voltage ratios. As per the question on page 45, the transformer ratio is 5:1, yet the answer in the back is based on the line voltage ratio of (600v:208v or 2.885:1). the answer for that question 6 is correct, however Figure 28 does not explain this at all. An update to the figure to state 'Line Voltage Ratio', or just some voltage values would better explain this rule.
Status: Implemented


Archived Comments

Year: 2021

11/24/2021 11:08:56 AM
Module: 030304c
Version: 22
Page: 36
Comment: Answer key is incorrect for Objective Four Exercise Answers 3-5: 3) Rule should be 26-602 4) Rule should be 26-600 5) Rule should be 26-600 Indicated Subrules are correct.
Status: Implemented

9/16/2021 3:34:04 PM
Module: 030302b
Version: 23
Page: 9
Comment: Table 2. Formula 4th row. rotor speed should be: N.r = N.syn - N.s slip speed can be added : N.s = S x N.syn
Status: Implemented

9/16/2021 3:13:27 PM
Module: 030303a
Version: 23
Page:
Comment: Figure 28 and 31. When referring back to these diagrams from Autotransformers module, the current direction arrows are totally opposite direction. When H and X terminals are not jumpered, then yes the induced voltage and current directions of the mutual inductance transformers would be correct. But when joined, the current direction flow will be based on the resultant voltage, which is incorrect according to the diagrams. I dont believe these diagrams are trying to convey actual current flow direction so maybe changing the labelling from 'current flow' to 'voltage polarity' is better. I could be missing something here, but the madness in my head says something is wrong here.
Status: Declined

2/19/2021 9:15:21 AM
Module: 030304e
Version: 21
Page: 2
Comment: The default NOTEs on page 2 should be changed from Class A Motor to Class B motor because the B type is absolutely the MOST common rotor type B AND insulation class B. If there is yet another classification method of motors, I am unaware of it and it is not described in any of the other ILM modules. Also, Figure 3 from this module shows a 480 Volt CONTROL CIRCUIT which is ridiculous because the default would be a 120 Volt control circuit supplied through a control transformer for 3 phase motor starters of 460 V or 575 V motors.
Status: Implemented

2/18/2021 1:59:41 PM
Module: 030304e
Version: 21
Page:
Comment: 2 Suggested corrections for ILM Motor Banks Code module 030304e: The default NOTEs on page 2 should be changed from Class A Motor to Class B motor because the B type is absolutely the MOST common NEMA rotor type B and NEMA insulation class B unless there is yet another motor classification that I am not aware of. Also, Figure 3 from this module shows a 480 Volt CONTROL CIRCUIT which is highly improbable. The default should be a 120 Volt control circuit supplied through a control transformer inside 3 phase motor starters of 460 V or 575 V motors.
Status: Implemented

2/8/2021 1:02:33 PM
Module: 030304e
Version:
Page: 1
Comment: Objective 3 states “Determine the maximum allowable ampacity of an overcurrent device for a group of motors”; however, the term “ampacity” is used incorrectly as “allowable ampacity” is for conductors, not overcurrent devices. That phrase is right from the title of Table 2. This objective should be reworded as “Determine the maximum ampere rating for an overcurrent device required for a group of motors”. This wording would match well with the wording of Objective 6 in the “Individual Motors” ILM (030304d).
Status: Declined

Year: 2020

1/31/2020 4:01:12 PM
Module: 030302b
Version: 21
Page: 37
Comment: Page 27 – Question 3 – Answer Key Page 37 – The answer for question 3 should be D
Status: Implemented

Year: 2019

11/7/2019 7:10:38 AM
Module: 030302a
Version: 21
Page: 33
Comment: The formula to calculate inrush VA is incorrect. Based on the the formula, the larger the motor the smaller the inrush VA would be. Example is if you have a 10 HP motor the inrush will be 10 times less than a 1 HP motor. The KVA required to start a motor is simply KVA multiplied by it's HP.
Status: Implemented

10/10/2019 9:05:13 AM
Module: 030303e
Version: 21
Page: 8
Comment: The first paragraph provides a reference to CEC Rule 4-038, subrules (4) and (5). Please change it to Rule 4-032 to reflect the change in the 2018 edition. The subrules remain the same. Thank you.
Status: Implemented

10/10/2019 8:55:17 AM
Module: 030303d
Version: 21
Page: 17
Comment: The second last bullet point references Rule 4-038(4) of the CEC. Please change it to Rule 4-032 4) to reflect the change in the 2018 edition. Thank you.
Status: Implemented

10/10/2019 8:42:27 AM
Module: 030301d
Version: 21
Page: 47
Comment: The last paragraph, below Figure 53, references Rule 4-038 (4) of the Canadian Electrical Code. Please change the Rule to 4-032 4) to reflect the change in the 2018 edition. Thank you.
Status: Implemented

1/1/2019 12:00:00 AM
Module: 030302a
Version: 7
Page: 26
Comment: This module conflates the direction of induced current flow with the direction of electron flow. Electrons have negative charge, and so the direction they flow in is the direction of negative current, which is opposite to the direction of positive current. Consider for example questions 2 and 3 of Objective Three exercise. They are essentially the same question, but the answer given for question 3 is the opposite of the answer given for question 2. Please correct this conflation; direction of induced current is *not* the same as the direction of electron flow.
Status: Declined

1/1/2019 12:00:00 AM
Module: 030304h
Version: 8
Page: 7
Comment: Rule 2-112 is incorrect. Should be rule 2-116 Corrosion Protection for Materials Used in Wiring.
Status: Implemented

1/1/2019 12:00:00 AM
Module: 030304b
Version: 11
Page: 43
Comment: Question 6 is okay. The 5 to 1 ratio is not needed to answer the question but having it there just makes the student think more. The ratio indicates that the transformer is a delta-wye connection. If you work through the question using the current values you will still get the correct answer. However, the code states that the secondary conductor ampacity is calculated by multiplying the primary conductor ampacity by the voltage ratio which is 600/208 = 2.885.
Status: Declined

1/1/2019 12:00:00 AM
Module: 030304b
Version: 11
Page: 43
Comment: I would like to ammend my comment that starts "Question 6 is okay". I think the 5 to 1 ratio should be removed because this is a code question not a theory question. Knowing that the transformer is a delta-wye connection is not needed to determine the conductor sizes.
Status: Declined

1/1/2019 12:00:00 AM
Module: 030302b
Version: 8
Page: 7
Comment: The reactance of the rotor is mostly inductive reactance because the rotor's capacitive reactance is miniscule" An induction motor does not have any capacitive reactance because it doesn't have a capacitor. Cap-start motors haven't been introduced yet other than a brief sentence in 2nd year for series RLC. Please remove or change to the rotor's reactance is all inductive reactance.
Status: Implemented